Thread plating allowance calculator
Plating grows a thread’s pitch diameter four times faster than its outside diameter. This works out how much room is left between the minimum thickness your drawing specifies and the ceiling the thread allowance imposes, before the parts come back and will not gauge.
Your thread
Allowances are computed, not copied. This uses the published ASME B1.1 allowance formula rather than a reproduced table, so you can check any value by hand: allowance = 0.300 × (0.0015 D1/3 + 0.0015 √LE + 0.015 P2/3), with the length of engagement LE taken as D. It reproduces the published figures exactly. 1/4-20 gives 0.0011 in, #10-24 gives 0.0010 in, 1-8 gives 0.0020 in.
Editions. The reasoning here was checked against ASTM B633-19, ASTM F1941/F1941M-10 and ISO 4042:2022. Later editions exist and govern: B633-23, and F1941/F1941M-16(2025), which was also retitled to cover metric fasteners. Clause numbers are deliberately not printed, because they move between revisions.
Result
Why the factor is four
A thread has two different surfaces and plating treats them differently.
On a fully formed flat crest the surface normal is radial, so a coating of thickness t adds t to each side and the outside diameter grows by about 2t, which is what a micrometer reads. Treat that as the idealised case: real rolled crests are not true cylinders, and a metrology dispute exists over whether major and minor diameters take a 2× or a 4× adjustment. The 4× on pitch diameter is not in dispute.
The flanks sit at 30° to the thread axis. The same coating displaces each flank along the pitch line by t ÷ sin 30°, and there are two flanks, so the pitch diameter grows by 2t ÷ sin 30° = 4t. Exactly four, not approximately.
That is the whole problem in one sentence: a plated screw can measure perfectly across the crests and still be rejected by a ring gauge, because the gauge reads the pitch diameter and the pitch diameter moved twice as fast as the part you measured.
For 29° Acme the half angle is 14.5° and the factor becomes 2 ÷ sin 14.5° = 7.99, near enough to eight.
Every UNC size, and the headroom it leaves
Computed live from the formula above. Each specification column shows the headroom in micrometres between that specified minimum and the gauge ceiling for that size. Green is a workable window, amber is under 2 µm and too tight for most production processes to hold, and no means the floor is already above the ceiling.
The result worth knowing before you write a drawing note: ASTM B633 SC4 does not fit any standard UNC thread. SC4 asks for a 25 µm minimum and the largest ceiling in the entire series, at 4 inch diameter, is 21.59 µm.
| Size | 2A allowance (in) | Gauge ceiling (µm) | SC1 5µm | SC2 8µm | SC3 12µm | SC4 25µm |
|---|---|---|---|---|---|---|
| #1-64 | 0.0006 | 3.81 | no | no | no | no |
| #2-56 | 0.0006 | 3.81 | no | no | no | no |
| #3-48 | 0.0007 | 4.45 | no | no | no | no |
| #4-40 | 0.0008 | 5.08 | 0.1 | no | no | no |
| #5-40 | 0.0008 | 5.08 | 0.1 | no | no | no |
| #6-32 | 0.0008 | 5.08 | 0.1 | no | no | no |
| #8-32 | 0.0009 | 5.71 | 0.7 | no | no | no |
| #10-24 | 0.0010 | 6.35 | 1.4 | no | no | no |
| #12-24 | 0.0010 | 6.35 | 1.4 | no | no | no |
| 1/4-20 | 0.0011 | 6.99 | 2.0 | no | no | no |
| 5/16-18 | 0.0012 | 7.62 | 2.6 | no | no | no |
| 3/8-16 | 0.0013 | 8.25 | 3.3 | 0.3 | no | no |
| 7/16-14 | 0.0014 | 8.89 | 3.9 | 0.9 | no | no |
| 1/2-13 | 0.0015 | 9.53 | 4.5 | 1.5 | no | no |
| 9/16-12 | 0.0016 | 10.16 | 5.2 | 2.2 | no | no |
| 5/8-11 | 0.0017 | 10.79 | 5.8 | 2.8 | no | no |
| 3/4-10 | 0.0018 | 11.43 | 6.4 | 3.4 | no | no |
| 7/8-9 | 0.0019 | 12.06 | 7.1 | 4.1 | 0.1 | no |
| 1-8 | 0.0020 | 12.70 | 7.7 | 4.7 | 0.7 | no |
| 1 1/8-7 | 0.0022 | 13.97 | 9.0 | 6.0 | 2.0 | no |
| 1 1/4-7 | 0.0022 | 13.97 | 9.0 | 6.0 | 2.0 | no |
| 1 3/8-6 | 0.0024 | 15.24 | 10.2 | 7.2 | 3.2 | no |
| 1 1/2-6 | 0.0024 | 15.24 | 10.2 | 7.2 | 3.2 | no |
| 1 3/4-5 | 0.0027 | 17.14 | 12.1 | 9.1 | 5.1 | no |
| 2-4 1/2 | 0.0029 | 18.41 | 13.4 | 10.4 | 6.4 | no |
| 2 1/4-4 1/2 | 0.0029 | 18.41 | 13.4 | 10.4 | 6.4 | no |
| 2 1/2-4 | 0.0031 | 19.68 | 14.7 | 11.7 | 7.7 | no |
| 2 3/4-4 | 0.0032 | 20.32 | 15.3 | 12.3 | 8.3 | no |
| 3-4 | 0.0032 | 20.32 | 15.3 | 12.3 | 8.3 | no |
| 3 1/4-4 | 0.0033 | 20.95 | 16.0 | 13.0 | 9.0 | no |
| 3 1/2-4 | 0.0033 | 20.95 | 16.0 | 13.0 | 9.0 | no |
| 3 3/4-4 | 0.0034 | 21.59 | 16.6 | 13.6 | 9.6 | no |
| 4-4 | 0.0034 | 21.59 | 16.6 | 13.6 | 9.6 | no |
Why this is a band and not a pass or fail. B633 service condition classes and F1941 designations are minimum thicknesses; the standards set no maximum. The allowance gives a ceiling on the maximum local thickness anywhere on the thread, including the high-current-density tips. So the useful question is not whether the specified number sits below the ceiling, it is how much room lies between them. A floor 1 µm under the ceiling is geometrically possible and not producible.
How plated threads are actually controlled. Both B633 and F1941 normally exempt threads, holes, deep recesses and the bases of angles from minimum thickness requirements, and F1941 observes that measuring coating thickness on a threaded portion is impractical. The control mechanism for a plated thread is the gauge, not a thickness reading. This calculator tells you whether what you specified can physically fit. It does not replace gauging, and it is not a substitute for talking to your plater before the drawing is released.
Common questions
Because they are different surfaces. The crest of a thread is a cylinder, so a coating of thickness t adds t to each side and the outside diameter grows by 2t. The flanks sit at 30 degrees to the thread axis, so the same coating displaces the flank by t divided by the sine of 30 degrees on each side. That works out to a pitch diameter growth of exactly 4t. A plated screw can measure correctly across the crests on a micrometer and still be rejected by a ring gauge, because the gauge is reading the pitch diameter.
The Class 2A pitch diameter allowance for 1/4-20 UNC computes to 0.0011 inch. Since coating consumes that allowance at four times its thickness, the gauge ceiling is 0.0011 divided by 4, which is 0.000275 inch, just under 7 micrometres. Read that as a ceiling on the maximum local thickness anywhere on the thread. ASTM B633 SC1 asks for a 5 micrometre minimum, which leaves under 2 micrometres of headroom, so it is geometrically possible but tight for production control. SC2 at 8 micrometres is already above the ceiling and will not gauge.
Not on a standard UNC thread. SC4 calls for 25 micrometres. The largest Class 2A allowance in the UNC series, at 4 inch diameter, computes to 0.0034 inch, giving a ceiling of 0.00085 inch or 21.59 micrometres. Every standard UNC size from #1 up to 4 inch has a ceiling below 25 micrometres, so SC4 does not fit any of them. The thread has to be cut undersize before plating, the class relaxed, or the coating specified thinner.
A Class 3A external thread is cut to basic size with no allowance at all, so there is no room for any coating whatsoever. Any plating at all pushes the pitch diameter over the maximum. A 3A thread that has to be plated must be cut undersize before plating.
Standard internal threads carry no allowance, so there is nothing to consume. The remedy is to tap oversize before plating. One tap H number is 0.0005 inch of pitch diameter, and since coating moves pitch diameter at four times its thickness, one H number corresponds to 0.000125 inch, about 3.2 micrometres, of plating.
Not because mechanical deposition changes the geometry. The four times relationship comes from the thread angle and applies to any coating however it is deposited, and ASTM B695 itself warns about buildup in thread roots. What makes heavy coatings assemble is the nut. ASTM A563 covers nuts tapped oversize for use with hot-dip and mechanically zinc-coated externally threaded fasteners, so the clearance for the coating comes from the nut rather than from the bolt thread allowance. If you need a heavy zinc coating on a threaded part, the overtapped nut is the mechanism to specify.
Yes, on anything longer than about five diameters. ISO 4042 Annex D.3 notes that local coating thickness at mid-length runs roughly one third to one half of the thickness at the extremities, because current density is higher at the ends. So plating enough to reach the specified minimum in the middle drives the ends to roughly two to three times that figure, and it is the ends that have to stay under the gauge ceiling. Enter a length in the calculator and it will flag this.
Send us the part
If the calculator says it does not fit, MFI can tell you what will. Send the drawing, the material and the volume.